GENERAL CHEMISTRY HW HELP!! due at 12pm
#1
09-29-2009, 12:45 AM
GENERAL CHEMISTRY HW HELP!! due at 12AM MIDNITE!
Enter text here.An acid solution is 0.120 M in HCL and .210 M in H2SO4, what volume of a .150 M KOH solution would have to be added to 500.0 mL of the acidic solution to neutralize completely all of the acid?
any freakin cluee how to do this!??!?!?
:confused ::confused : ive been working for like 2hours on this. its due online at 12pm so any quick help would be very appreciated! ill let u have a import tuner magazine or something lol
any freakin cluee how to do this!??!?!?
:confused ::confused : ive been working for like 2hours on this. its due online at 12pm so any quick help would be very appreciated! ill let u have a import tuner magazine or something lol
Last edited by Evan_2k; 09-29-2009 at 01:34 AM.
#4
09-29-2009, 01:48 AM
hope this help........
0.5000 litres @ 0.120mol/litre = 0.0600 moles of HCl, which releases 0.0600 moles of H+ ion
0.5000 litres of 0.210 mol/litre = 0.105 moles of H2SO4, which releases 0.210 moles of H+ ion
0.210 & 0.060 = a total of 0.270 moles of H+ ion
-----------------------------------------------------------------------------
0.270 moles of H+ ion needs 0.270 moles of OH- ion
0.270 moles of OH- ion @ 0.150 mol/litre = 1.80 litres of KOH
your answer: 1.80 litres of 0.150 M KOH
0.5000 litres @ 0.120mol/litre = 0.0600 moles of HCl, which releases 0.0600 moles of H+ ion
0.5000 litres of 0.210 mol/litre = 0.105 moles of H2SO4, which releases 0.210 moles of H+ ion
0.210 & 0.060 = a total of 0.270 moles of H+ ion
-----------------------------------------------------------------------------
0.270 moles of H+ ion needs 0.270 moles of OH- ion
0.270 moles of OH- ion @ 0.150 mol/litre = 1.80 litres of KOH
your answer: 1.80 litres of 0.150 M KOH
#5
09-29-2009, 02:27 AM
hope this help........
0.5000 litres @ 0.120mol/litre = 0.0600 moles of HCl, which releases 0.0600 moles of H+ ion
0.5000 litres of 0.210 mol/litre = 0.105 moles of H2SO4, which releases 0.210 moles of H+ ion
0.210 & 0.060 = a total of 0.270 moles of H+ ion
-----------------------------------------------------------------------------
0.270 moles of H+ ion needs 0.270 moles of OH- ion
0.270 moles of OH- ion @ 0.150 mol/litre = 1.80 litres of KOH
your answer: 1.80 litres of 0.150 M KOH
0.5000 litres @ 0.120mol/litre = 0.0600 moles of HCl, which releases 0.0600 moles of H+ ion
0.5000 litres of 0.210 mol/litre = 0.105 moles of H2SO4, which releases 0.210 moles of H+ ion
0.210 & 0.060 = a total of 0.270 moles of H+ ion
-----------------------------------------------------------------------------
0.270 moles of H+ ion needs 0.270 moles of OH- ion
0.270 moles of OH- ion @ 0.150 mol/litre = 1.80 litres of KOH
your answer: 1.80 litres of 0.150 M KOH
you are a god... the H+ releasing from h2so4 was tricky!!! theres 2 god damn hydrogens!! i kept getting it wrong and it wouldnt let me submit,now I know why..... You can do this problem and not wire my foglight?? lol im jk, thank you so much peter i owe u one!
#8
09-29-2009, 03:26 AM
Went to JH for the Summer program for Civil Engineering program now I'm at Cal State Fullerton and Santa Ana College, now I putting transfer paper to Alaska Pacific University or CU Boulder or Oregon State or USC to finish up my study and research in Environmental Geology/ Engineering....
#9
09-29-2009, 03:41 AM
clicked the thread thinking "OOH! unemployed chemist to the rescue!!!"
lol but damn... peter beat me to it!!! i didnt see it till now... haha oh well he's got it...
if u ever need more help peter and i got your back
lol but damn... peter beat me to it!!! i didnt see it till now... haha oh well he's got it...
if u ever need more help peter and i got your back
